1953 FIFA Youth Tournament Under-18
The FIFA Youth Tournament Under-18 1953 Final Tournament was held in Belgium. Argentina was the first non-European team that entered.
Tournament details | |
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Host country | Belgium |
Dates | 31 March – 6 April |
Teams | 16 |
Final positions | |
Champions | Hungary (1st title) |
Runners-up | Yugoslavia |
Third place | Turkey |
Fourth place | Spain |
Tournament statistics | |
Matches played | 32 |
Teams
The following teams entered the tournament:
- Argentina (invited)
- Austria
- Belgium (host)
- England
- France
- West Germany
- Hungary
- Luxembourg
- Netherlands
- Northern Ireland
- Republic of Ireland
- Saarland
- Spain
- Switzerland
- Turkey
- Yugoslavia
First round
England | 2 – 0 | Belgium |
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West Germany | 3 – 2 | Argentina |
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Hungary | 4 – 0 | Switzerland |
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Republic of Ireland | 1 – 0 | Netherlands |
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Luxembourg | 4 – 3 | Austria |
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Spain | 5 – 0 | Saarland |
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Turkey | 1 – 0 | France |
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Yugoslavia | 5 – 1 | Northern Ireland |
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Quarterfinals
Places 9-16
France | 2 – 1 | Austria |
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Netherlands | 2 – 1 | Switzerland |
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Belgium | 4 – 3 | Northern Ireland |
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Argentina | 7 – 0 | Saarland |
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Semifinals
Final Matches
Fifteenth Place Match
Northern Ireland | 2 – 1 | Austria |
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Thirteenth Place Match
Switzerland | 2 – 2 Saar refused to play Extra Time | Saarland |
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Eleventh Place Match
Belgium | 4 – 3 | France |
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Ninth Place Match
Argentina | 3 – 1 | Netherlands |
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Seventh Place Match
Luxembourg | 3 – 2 | West Germany |
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Fifth Place Match
England | 2 – 0 | Republic of Ireland |
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Third place match
Turkey | 3 – 2 | Spain |
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