Doubles
1978 Virginia Slims of Philadelphia
ChampionsAustralia Kerry Reid
Australia Wendy Turnbull
Runners-upFrance Françoise Dürr
United Kingdom Virginia Wade
Score6–3, 7–5

Françoise Dürr and Virginia Wade were the defending champions, but lost in the final to Kerry Reid and Wendy Turnbull. The score was 6–3, 7–5.

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Australia K Reid
Australia W Turnbull
6 6
United Kingdom G Coles
United States Z Liess
4 1 1 Australia K Reid
Australia W Turnbull
6 6
United States B Potter
West Germany R Tomanová
62 2 United States L Antonoplis
United States P Teeguarden
4 2
United States L Antonoplis
United States P Teeguarden
75 6 1 Australia K Reid
Australia W Turnbull
6 6
4 United States R Casals
United States J Russell
6 6 4 United States R Casals
United States J Russell
4 3
Sweden H Anliot
Czechoslovakia R Maršíková
4 3 4 United States R Casals
United States J Russell
6 3 7
United States T Austin
Netherlands B Stöve
3 6 5
1 Australia K Reid
Australia W Turnbull
6 7
United States L duPont
United States K May
7 6 3 France F Dürr
United Kingdom V Wade
3 5
United Kingdom M Tyler
South Africa Y Vermaak
5 4 United States L duPont
United States K May
6 0 4
West Germany K Ebbinghaus
Romania F Mihai
2 0 3 France F Dürr
United Kingdom V Wade
2 6 6
3 France F Dürr
United Kingdom V Wade
6 6 3 France F Dürr
United Kingdom V Wade
6 7
Australia D Fromholtz
Australia L Hunt
2 5 2 United States J Newberry
United States K Shaw
4 5
Socialist Federal Republic of Yugoslavia M Jaušovec
Romania V Ruzici
6 7 Socialist Federal Republic of Yugoslavia M Jaušovec
Romania V Ruzici
6 2 6
2 United States J Newberry
United States K Shaw
4 6 7

References

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