1886 Rhode Island gubernatorial election

April 7, 1886
 
Nominee George P. Wetmore Amasa Sprague George H. Slade
Party Republican Democratic Prohibition
Popular vote 14,340 9,944 2,585
Percentage 53.36% 37.00% 9.62%

Governor before election

George P. Wetmore
Republican

Elected Governor

George P. Wetmore
Republican

The 1886 Rhode Island gubernatorial election was held on April 7, 1886. Incumbent Republican George P. Wetmore defeated Democratic nominee Amasa Sprague with 53.36% of the vote.

General election

Candidates

Major party candidates

Other candidates

  • George H. Slade, Prohibition

Results

1886 Rhode Island gubernatorial election[1][2][3][4][5][lower-alpha 1]
Party Candidate Votes % ±%
Republican George P. Wetmore (incumbent) 14,340 53.36%
Democratic Amasa Sprague 9,944 37.00%
Prohibition George H. Slade 2,585 9.62%
Scattering 6 0.02%
Majority 4,396 16.36%
Turnout 26,875
Republican hold Swing

Notes

  1. Some sources gives Sprague's vote as 9,994.[6][7]

References

  1. Dubin, Michael J. (2010). United States Gubernatorial Elections, 1861-1911. Jefferson, NC: McFarland & Co. p. 14. ISBN 978-0-7864-4722-0.
  2. Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 272–273. ISBN 0-930466-17-9.
  3. Kallenbach, Joseph E.; Kallenbach, Jessamine S., eds. (1977). American State Governors, 1776-1976. Vol. I. Dobbs Ferry, N.Y.: Oceana Publications, Inc. p. 517. ISBN 0-379-00665-0.
  4. McPherson, Edward, ed. (1887). The Tribune Almanac and Political Register for 1887. New York, NY: The Tribune Association. p. 79.
  5. Manual with Rules and Orders for the use of the General Assembly of the State of Rhode Island. 1886-7. Providence, R. I.: E. L. Freeman & Son, State Printers. 1886. pp. 91–92.
  6. "RI Governor, 1886". Our Campaigns. Retrieved September 14, 2021.
  7. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved October 14, 2020.
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