1810 Delaware gubernatorial election

October 2, 1810
 
Nominee Joseph Haslet Daniel Rodney
Party Democratic-Republican Federalist
Popular vote 3,664 3,593
Percentage 50.49% 49.51%

Governor before election

George Truitt
Federalist

Elected Governor

Joseph Haslet
Democratic-Republican

The 1810 Delaware gubernatorial election was held on October 2, 1810.

Incumbent Federalist Governor George Truitt was not eligible for re-election under the Delaware Constitution of 1792.

Democratic-Republican nominee Joseph Haslet defeated Federalist nominee Daniel Rodney with 50.49% of the vote.

General election

Results

1810 Delaware gubernatorial election[1][2][3][4]
Party Candidate Votes % ±%
Democratic-Republican Joseph Haslet 3,664 50.49%
Federalist Daniel Rodney 3,593 49.51%
Majority 71 0.98%
Turnout 7,257 100.00%
Democratic-Republican gain from Federalist Swing

References

  1. "DE Governor, 1810". Our Campaigns. Retrieved December 8, 2020.
  2. Congressional Quarterly 1998, p. 46.
  3. Glashan 1979, pp. 50–51.
  4. Dubin 2003, p. 26.

Bibliography

  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.


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