supercuspidal

English

Etymology

super- + cuspidal

Adjective

supercuspidal (not comparable)

  1. (mathematics) That has a zero Jacquet functor for every proper parabolic subgroup
    • 2015, Manish Mishra, “A Galois side analogue of a theorem of Bernstein”, in arXiv:
      A theorem of Bernstein states that for any compact open subgroup of , there are, up to unramified twists, only finitely many -spherical supercuspidal representations of .
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