Pomeroy, Iowa
Pomeroy is a city in Calhoun County, Iowa, United States. The population of Pomeroy was 526 in 2020.[2]
Pomeroy, Iowa | |
|---|---|
 Location of Pomeroy, Iowa | |
| Coordinates: 42°32′54″N 94°41′1″W | |
| Country |  United States |
| State |  Iowa |
| County | Calhoun |
| Government | |
| • Type | Mayor-council |
| Area | |
| • Total | 2.05 sq mi (5.30 km2) |
| • Land | 2.05 sq mi (5.30 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 1,240 ft (378 m) |
| Population | |
| • Total | 526 |
| • Density | 256.84/sq mi (99.17/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 50575 |
| Area code | 712 |
| FIPS code | 19-64065 |
| GNIS feature ID | 0460354 |
| Website | City of Pomeroy |
Pomeroy was hit by a tornado on July 6, 1893, that was estimated to be F5 on the Fujita scale. There was a damage path of around 500 yards (460 m) wide and 55 miles (89 km) long and the tornado destroyed about 80% of the homes in Pomeroy. It killed 71 people and injured 200 others.
References
- "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- "Pomeroy city, Iowa". United States Census Bureau. Retrieved November 9, 2023.
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