1888 Belgian general election

12 June 1888 (1888-06-12)

69 of the 138 seats in the Chamber of Representatives
70 seats needed for a majority
  First party Second party
 
Leader Auguste Beernaert
Party Catholic Liberal
Leader since Candidate for PM
Seats before 98 seats 40 seats
Seats won 66 3
Seats after 98 40
Seat change Steady Steady
Popular vote 31,273 19,967
Percentage 58.44% 37.31%

Government before election

Beernaert
Catholic

Government after election

Beernaert
Catholic

Partial general elections were held in Belgium on 12 June 1888.[1][2] The result was a victory for the Catholic Party, which won 98 of the 138 seats in the Chamber of Representatives and 47 of the 69 seats in the Senate.[2]

Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.

Results

Chamber of Representatives

PartyVotes%Seats
WonTotal+/–
Catholic Party31,27358.4466980
Liberal Party19,96737.313400
Others2,2774.2500New
Total53,517100.00691380
Total votes53,517
Registered voters/turnout73,27673.03
Source: Mackie & Rose,[3] Sternberger et al.

Senate

PartySeats
Catholic Party47
Liberal Party18
Independents4
Total69
Source: Sternberger et al.

References

  1. Codebook Constituency-level Elections Archive, 2003
  2. 1 2 Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
  3. Thomas T. Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp50–51
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